Determining the Digits of a Number
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Which C++ operation is used to determine the last digit of a number?
- A)It becomes double the value
- B)It is reduced by one digit
- C)It is set to 0
- D)It becomes the last digit
- A)27
- B)274
- C)2
- D)0
- A)The first digit
- B)The last digit of the truncated value
- C)The second to last digit
- D)The initial value of n
- A)It continues as long as n is positive
- B)It runs only if n is zero
- C)It terminates when n is zero
- D)It counts the digits of n
- A)0
- B)No output
- C)An error message
- D)The number of digits in 'n'
- A)Hundreds
- B)Tens
- C)Units
- D)All digits sequentially
- A)Digits are shown from first to last
- B)Digits are shown in reverse order
- C)Only the last digit is shown
- D)Only the first digit is shown
- A)Nothing, as it's retained automatically
- B)Use the same variable 'n'
- C)Store it in a different variable
- D)Delete the program
- A)To add more digits
- B)To check if 'n' is zero
- C)To eliminate the last digit for next extraction
- D)To increase its value
What happens to the variable 'n' after executing 'n = n / 10'?
After applying 'n = n / 10' on 'n = 274', what is the new value of 'n'?
What does the operation 'n % 10' return after 'n' has been truncated?
What does 'while(n != 0)' ensure in the provided program?
What is printed when 'n' is zero in the program?
Which digit is determined with the expression 'n % 10' before truncation?
What key observation is made about the order of digits displayed in the program?
What should be done if we need to keep the initial value of 'n' after digit extraction?
What is the significance of truncating 'n' in the digit extraction process?